George and a total of $592 in simplest interest from two separate accounts. In an account earning 6% interest, George invested $1800 more than three times the amount he invested in an account earning 4%. How much did he invests in each account

The amount invested at 4% is $2,200 and the amount invested at 6% is $8,400

Step-by-step explanation:

we know that

The simple interest formula is equal to

where

I is the Final Interest Value

P is the Principal amount of money to be invested

r is the rate of interest  

t is Number of Time Periods

Let

x ----> the amount invested at 4%

(3x+1,800) -----> the amount invested at 6%

we have that

The interest earned by the account at 4% plus the interest earned by the amount at 6% must be equal to $592

so

The linear equation that represent this situation is

solve for x

therefore

The amount invested at 4% is $2,200 and the amount invested at 6% is $8,400

a = 3.14

b = 18

c = 18/5 or 3.6 or 3 3/5

step-by-step explanation: