One person is selected at random from a class of 20 males and 13 females. Find the odds against selecting a male and a female

Odds for male= 1.538

Odds for female =  0.65

Step-by-step explanation:

The question is asking for odds, not a probability. A probability shows how much the chance for the event to happen, so it can be expressed as a percentage. Odds show how the event more likely to happen compared to the chance it did not happen. If an event has a 90% probability, the odds will be 90:10= 9

In this case, the odds of selecting a male will be:  

number of male : number of female= 20:13 = 1.538

The odds of selecting a female will be

number of female : number of male = 13/20 = 0.65

is should be y = 5x

step-by-step explanation:

correct me if im wrong

u = -(6/7)w

step-by-step explanation:

place all values with 'u' on one side of the equation.

4u + 8w = - 3u + 2w

4u + 3u = 2w - 8w

further simplify the equation by solving the addition and subtraction.

7u = - 6w

make 'u' the independent variable by placing its co-efficient on the right-hand side.

u = - (6/7)w