A person plans to invest a total of $3500 in one bank account at 2.2% annual interest and another bank account at 17% annual interest. How much should he invest in each account so that the total interest in one year will be $151?

$435.3

Step-by-step explanation:

Assuming simple interest

Interest, I=Pi/100 where P is principal amount and i is rate of interest in percentage

For $3500, the interest will be 3500*2.2/100=$77

From total target of $151, the person is less 151-77=$74

Taking x as principal and rate of interest as 17% then

0.17x=74

X=74/0.17=$435.2941176470

Rounded off as $435.3

x = ±sqrt(10)

step-by-step explanation:

5 - 2x² = -15

subtract 5 from each side

5-5 - 2x² = -15-5

-2x^2   = -20

divide by -2 on each side

-2x^2   /-2= -20/-2

x^2 =10

take the square root on each side

sqrt(x^2 )=±sqrt(10)

x = ±sqrt(10)

check:

5 - 2x² = -15

+sqrt(10)

5 - 2(sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15

-sqrt(10)

5 - 2(-sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15