3x+4y=14
x=2y-12
which point satisfies both equations

The point that satisfies both equations are (-2, 5)

That is, x = -2 and y = 5

Step-by-step explanation: What we have here is a pair of simultaneous equations which are

3x + 4y = 14 (1)

x = 2y - 12 (2).

The point that satisfies both equations would be the value of x and y that would make both equations correct. In other words, calculate x and y.

From equation (2), x = 2y - 12.

Substitute for the value of x into equation (1)

3(2y - 12) + 4y = 14

6y - 36 + 4y = 14

We collect like terms and we now have

6y + 4y = 14 + 36

10y = 50

Divide both sides of the equation by 10

y = 5

Having calculated the value of y, substitute for the value of y into equation (2)

x = 2(5) - 12

x = 10 - 12

x = -2

Therefore, the point is where x = -2 and y = 5

341

step-by-step explanation:

all you have to do is 9x31 (which equals 279) and then 20x31 (which equals 620). then you have to subtract. 620-279=341.

so firstly, we need to isolate the y variables to be able to solve these inequalities. firstly, add 0.5x on both sides of the first inequality and subtract 1.5x on both sides of the second inequality:

now since the slope is positive for the first inequality, this means that the line going upwards belongs to the first inequality, and the line going downwards belongs to the second inequality.

next, since y ≥ in the first inequality, this means that the shaded region will be above the first inequality's line, thus shading regions a and b.

next, since y ≤ in the second inequality, this means that the shaded region is going to be below this line, thus shading regions a and c.

since both lines shade region a, this means that region a is the solution.

step-by-step explanation:

mark brainliest!