Mathematics, 21.03.2020 21:14 mervindavisk

Plz help me and plz show the work I have been stuck on this for hours

Plz help meeeeeee and plz show the work I have been stuck on this for hours

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Answer from: jwoodsk7598

Bryson bought $2\frac{3}{4}$ pounds of veggie burgers for $8.80.Part A) What is the unit price per pound of the veggie burgers? Show your work

Total pounds of veggie burgers $=2\frac{3}{4}=\frac{11}{4}$

Cost of $2\frac{3}{4}$ pounds of burgers = $8.80

The unit price per pound of the veggie burgers:

$=8.80\:\div \frac{11}{4}$

$=\frac{8.8}{1}\div \frac{11}{4}$

$\mathrm{Apply\:rule}\:\frac{a}{1}=a$

$=8.8\times \frac{4}{11}$

$=\frac{4\times \:8.8}{11}$

$=\frac{35.2}{11}$

=3.2

Therefore, the unit price per pound of the veggie burgers: $3.2

Part B) There are 16 ounces in a pound. What is the unit price ounce of the veggie burgers.

Total pounds of veggie burgers $=2\frac{3}{4}=\frac{11}{4}$

Cost of $2\frac{3}{4}$ pounds of burgers = $8.80

Total number of ounces in a pound = 16

Total number of ounces in $2\frac{3}{4}$ pounds $=\frac{11}{4}\times \:16=44$

The unit price per ounce of the veggie burgers:

$=\frac{8.8}{44}$

=0.2

Therefore, the unit price per pound of the veggie burgers: $0.2

Part C) At that unit price, what is the price for $4\frac{1}{2}$ pounds of veggie burgers? Show your work.

As the unit price per pound of the veggie burgers: $3.2

The price for $4\frac{1}{2}$ pounds of veggie burgers:

$=4\frac{1}{2}\times 3.2$

$\mathrm{Convert\:mixed\:numbers\:to\:improper\:fractions}:\quad 4\frac{1}{2}=\frac{9}{2}$

$=\frac{9}{2}\times \:3.2$

$\mathrm{Multiply\:fractions}:\quad \:a\times \frac{b}{c}=\frac{a\:\times \:b}{c}$

$=\frac{9\times \:3.2}{2}$

$=\frac{28.8}{2}$

=14.4

Therefore, the price for $4\frac{1}{2}$ pounds of veggie burgers will be: $14.4

Answer from: Quest

Just a second zzz

Answer from: Quest

$w\geq 14$

the smallest possible measurement of the width is 14 feet

step-by-step explanation:

let's assume length of parallelogram is 'l'

width of parallelogram is 'w'

the perimeter of a parallelogram must be no less than 40 feet

so, we get

$2l+2w\geq 40$

we are given

length of parallelogram is 6 feet

so,

l=6

we can plug it

$2\times 6+2w\geq 40$

now, we can solve for w

$12+2w\geq 40$

subtract both sides by 12

$12+2w-12\geq 40-12$

$2w\geq 28$

divide both sides by 2

and we get

$w\geq 14$

so,

the smallest possible measurement of the width is 14 feet

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