Inside the square ABCD, side 15 cm, the point M is considered, so that the triangle ABM is equilateral. Show that:

a) The area of ABCD = 225 cm square,

b) The triangle MDC is isosceles,

c) PLEASE HELP ME!

a) 15*15=225 that is the area

b)see picture that I drew (sorry I have terrible drawing skills on a computer) but in a an isosceles triangle the two legs are congruent and the base is not when you cut a square diagonally as you have done this one the base will not be the same as the other two legs.

Step-by-step explanation:

Step-by-step explanation:

a) area of square: 15 x 15 = 225 cm²

b) The steps are illustrated in the picture.

ΔADM ≅ ΔBCM (sas)

DM = CM

ΔMDC is isoceles

b

step-by-step explanation:

if a was wrong then it has to be b it cant be c either because not all the y intercepts are the same!

ok now , i would like brainlest plz

answer: 75°

step-by-step explanation:

∠esk is the supplement of ∠edk, so is 100°. ∠esd = 1/2·arc ed, so is 25°.

since ∠esk = ∠esd + ∠dsk

you have 100° = 25° + ∠dsk . .

fill in known values 75° = ∠dsk . . . . .

subtract 25°

step-by-step explanation: