Solve the triangle, please help

Side A = 14; Side B = 24.25; Side C = 28 |

Angle A = 60 degrees; Angle B = 30 degrees; Angle C = 90 degrees

Step-by-step explanation:

Okay, I find this question a bit weird because you already have two sides

So, I'm going to assume:

Side A = 14

Side B = 24.25

Using Pythagoras theorem

c = 28 units (28.00111605)

In the diagram, we can see there is a right angle triangle, and a little square

Therefore, we can say that Angle C is 90 degrees

Finding Angle A/B:

There are so many ways to find it, I'll just use this though

Using SOHCAHTOA

I'll be using the sine rule to find Angle B

Angle B = 30 degrees

The interior angles in a triangle add up to 180 degrees

Angle A = 180 - (90 + 30)

Angle A = 60 degrees

Verify:

60 + 30 + 90 = 180

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