I need help on this question please ASAP

439.53 J

Step-by-step explanation:

Step 1:

Here the Liquid given is 15 L = 15 kg (1 L =1 kg)

Heat required is from 28°C to 35°C

Step 2:

The heat  required is given by

Where , Q = Heat required

m = Mass

C = 4.186 J  / g ° C

T₂ = 35° C

T₁ = 28° C

 Q =

Q= 439.53 J

438.9 kJ

Step-by-step explanation:

You take the total mass which is 15000g.

You take the specific heat capacity of water. 4.18J

You take the Celsius required to increase. 35-28 = 7

15000*4.18*7 = 438900 J ---> 438.9 kJ

area of part 1:

a1=base*height/2=(8+2)*(8-2-2-1)/2=10*3/2=15 ft^2

area of part 2:

a2=length*width=(8+2)*1=10 ft2

area of part 3:

a3=length*width=8*2=16 ft2

total shaded area : a1+a2+a3=41 ft2

total area of the reactangle : a=16*8=128 ft2

total area of the nonshaded region : 128-41=87 ft2

step-by-step explanation:

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