If a parabola with vertex (−2,1) also contains the point (1,6) which point must also be on the parabola?

a. (−3,6)
b. (−5,6)
c. (3,6)
d. (−7,4)

(-5,6)

Step-by-step explanation:

I graphed the points and found that (-5,6) would fall on the parabola.

The equation of the line is , if you need it.

If this answer is correct, please make me Brainliest!

since your problem is x^4 = 81, what you have to undeo is the "to the fourth power" part.

the inverse (opposite operation) of "to the fourth power" is "to the fourth root".

  (x^4) ^ ¼   = 81 ^ ¼  

  81 = 3^4     so (3 ^ 4) ^ ¼   =   3 ^ 1   = 3

by hand: (3 ^ 4) ^ ¼   =   3 ^ (4 x ¼) = 3 ^ 1   = 3   (when you take a power to a power, multiply the exponents.)

or, do it by calculator. one way of finding the fourth root is to use ^ (1/4)

step-by-step explanation: