What is the vertex of y=x^2+4x+3

(-2, -1)

Step-by-step explanation:

This is a quadratic equation in standard form, and a = 1, b = 4 and c = 3.

The x-coordinate of the vertex is given by the formula

        -b                                                                         -4

x = which here has the numerical value x = = -2

        2a                                                                           2

Finally, we evaluate y=x^2+4x+3 at x = -2 to find the y-coordinate of the vertex:

y = (-2)^2 + 4(-2) + 3 = -1

The vertex is at (-2, -1).

here you hope this .

step-by-step explanation:

hypotenuse = √(15² + 8²)

=  √(225 +64)

=  √(289) = 17

sin(x) = cos(y) = 8/17

they are identical so long as you are doing the sine of one angle and the cosine of the only other angle that isn't the right angle.

idk im srry

step-by-step explanation: