The amount a spring will stretch, S, varies directly with the weight, F, attached to the spring. If
a spring stretches 2.22 inches with 37 pounds attached, how far will it stretch when 25 pounds
are attached?
(1 point)
0.6 inches
16.67 inches
0.95 inches
1.5 inches

1.5 inches

Step-by-step explanation:

If two quantities are directly proportional, it means that an increase in the value of one quantity would cause a corresponding increase in the other quantity. Also, a decrease in the value of one quantity would cause a corresponding decrease in the other quantity.

Given that the amount a spring will stretch,S varies directly with weight, F, if we introduce a constant of proportionality, k, the expression becomes

S = kF

When S = 2.22 and L = 37, then

2.22 = 37k

k = 2.22/37 = 0.06

Therefore, the equation that relates the length S that the spring stretches to the weight F is

S = 0.06F

Therefore, if F = 25 pounds, then

S = 0.06 × 25

S = 1.5 inches

f(x) = x^3 -2x^2 -3x

x( x^2 -2x-3)

x( x^2 +x -3x -3)

x( x(x+1) -3(x+1))

x( x-3)( x+1)

so zeroes are 0, 3,-1

its (2) option