If f(x) = 1 – x, which value is equivalent to |f(i)|?

If f(x) = 1 – x then, value of |f(i)| is:

√2

Step-by-step explanation:

f(x) = 1 – x

Then, f(i) = 1 - i

We know that if f(z)=x+iy then, |f(z)|=

Hence,  |f(i)| =

                    =

                    = √2

Hence, if f(x) = 1 – x then, value of |f(i)| is:

√2

we know that

applying the law of sines

°

so

∠j=18°

∠k=29°

∠l=180-(18+29)=133°

the answer part a) is

the measure of angle k is  ≈29°

part b)  the measure of angle k could also be

(180-29)=151°

so

∠j=18°

∠k=151°

∠l=180-(18+151)=11°

the answer part b) is

the measure of angle k could also be 151°

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ou would have 12 of each