A distribution of values is normal with a mean of 220 and a standard deviation of 13. From this distribution, you are drawing samples of size 35. Find the interval containing the middle-most 48% of sample means:

The interval containing the middle-most 48% of sample means is between 218.59 to 221.41.

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean and standard deviation , the zscore of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributied random variable X, with mean and standard deviation , the sample means with size n can be approximated to a normal distribution with mean and standard deviation

In this problem, we have that:

Find the interval containing the middle-most 48% of sample means:

50 - 48/2 = 26th percentile to 50 + 48/2 = 74th percentile. So

74th percentile

value of X when Z has a pvalue of 0.74. So X when Z = 0.643.

By the Central Limit Theorem

26th percentile

Value of X when Z has a pvalue of 0.26. So X when Z = -0.643

The interval containing the middle-most 48% of sample means is between 218.59 to 221.41.

70,000 + 6,000 + 800 + 30

step-by-step explanation:

answer: idk

step-by-step explanation: