A line parallel to y=3/5x-3 and passing through the point (15,-2)

We will use point-slope form, where is the slope and is a known point on the line.

First, find the slope. Since the two lines will be parallel, they'll share the same slope of .

Substitute in the known point.

Simplify the negative subtraction.

Note: If you need the answer in a different form, please let me know below.

y = x - 11

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

y = x - 3 ← is in slope- intercept form

with slope m =

Parallel lines have equal slopes, thus

y = x + c ← is the partial equation of the parallel line

To find c substitute (15, - 2) into the partial equation

- 2 = 9 + c ⇒ c = - 2 - 9 = - 11

y = x - 11 ← equation of parallel line

r and t.

both are 64 degrees.

1. 523.33 cubic inches

2. 113.04 cubic inches.

3. 17.41.

4. 16.49

i think this should be your answer

hope i

-lavira : )