In a sample of 100 U. S. adults aged 18–24 who celebrate Halloween, the mean amount spent on a costume was $37.51 with a standard deviation of $16.44. A retail specialist claims that the mean amount spent on Halloween costumes for all U. S. adults aged 18–24 is between $35.07 and $39.95. With what level of confidence can this claim be made? Answer is 85.9%

The level of confidence is 86%.

Step-by-step explanation:

From the information given

Number of sample, n = 100

Mean, u = $37.51

Standard deviation, s = $16.44

Firstly, we would determine the upper and lower limits of the mean. Therefore,

For upper limit, it is

39.95 - 37.51 = 2.44

For lower limit, it is

37.51 - 35.07 = 2.44

Limit = ± 2.44

We will apply the formula

Confidence interval which is expressed as

= mean ± z × standard deviation/√n

It becomes

37.51 ± z × 16.44/√100

= 37.51 ± z × 1.644

= 37.51 ± 1.644z

Therefore,

1.644z = 2.44

z = 2.44/1.644 = 1.48

The level of confidence corresponding to the z value is 86%

john got lost so he didn't know what to do and it was crazy because he didn't except it

step-by-step explanation:

123123 step byt step

for the friend request.

when a figure, such as triangle (xyz) is reflected over the line y = x to create x'y'z' the x-coordinates and y-coordinates of the original image (pre-image) will be reversed for the image. (e.g., (x, y) > (y, x)) this means that the pre-image position of the x- and y-coordinates switch places which in turn provides a mirror like image of the original xyz.  

i notice that when i draw a line segment from x to x', that the points are parallel from each other -- they are exactly across from each other and do not intersect with any other points.  

yes, think i would see the same characteristic if you drew the line segment connecting y with the reflecting line and then y' with the reflecting line because of the essence of reflections. because it is a mirror image, each point was effected the same way which leads me to conclude that they same would apply to y and y'.