In the school cafeteria, students choose their lunch from 4 sandwiches, 3 soups, 3 salads, and 2 drinks. How many different lunches are possible for a student who chooses exactly 1 sandwich, 1 soup, 1 salad, and 1 drink?

In the school cafeteria, students choose their lunch from 4 sandwiches, 3 soups, 3 salads, and 2 drinks. There are 72 different lunches possible for a student who chooses exactly 1 sandwich, 1 soup, 1 salad, and 1 drink.

The combination of an object is the technique applied in choosing the possible number of combinations in an array of datasets.

It is can be expressed by using the formula:

where;  

To determine the number of different lunches that are possible in which students in the school cafeteria choose exactly 1 sandwich, 1 soup, 1 salad, and 1 drink, we have:

Therefore, we can conclude that there are 72 different lunches possible for a student who chooses exactly 1 sandwich, 1 soup, 1 salad, and 1 drink.

Learn more about combinations here:

link

72 different lunches

Step-by-step explanation:

As the student will pick one of each type, we can calculate the number of possibilities for each case, and them multiply all of them.

(if the student picks 1 in a group of 4, the number of different combinations we can do is 4)

For sandwiches, the student has 4 different combinations.

For soups, the student has 3 different combinations.

For salads, the student has 3 different combinations.

For drinks, the student has 2 different combinations.

So, the number of different lunches the stundent can make is 4*3*3*2 = 72

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step-by-step explanation:

ez do it yourself lazy

hi! i think the answer is 1/2 : )