A mass on a spring bounces up and down in simple harmonic motion, modeled by the function s ( t ) = 3 sin t(t)=3 sin t where s is measured in centimeters and t t is measured in seconds. Find the rate at which the spring is oscillating at t = 9 t=9 s. Round your answer to four decimal places.

Rate at which spring is oscillating 2.9631

Step-by-step explanation:

The governing equation for the position of the spring = 3 sin t

the change in position of the spring with respect to time is =

given time t = 9 seconds,

To find the rate at which the spring is oscillating at the time, we insert the time 9 seconds into the the slot for t

rate at which it is oscillating = 2.9631

28

step-by-step explanation:

because that's the answer

d 25 pi/6

step-by-step explanation:

the diameter is 10 inches

the radius is 1/2 of the diameter or 5 inches

the area of the circle is

a = pi r^2

  = pi 5^2

  = 25 pi

the slice is 60 degrees of the entire circle.

60 degrees out of 360   60/360 = 1/6

the area of the slice is 1/6 of the circle

a slice = 1/6 a circle

a slice = 1/6 * 25 pi