Mathematics, 20.03.2020 02:54 brose0707
1 point) Suppose we roll a fair six-sided die and sum the values obtained on each roll, stopping once our sum exceeds 318. Approximate the probability that at least 84 rolls are needed to get this sum.
Answers: 2
![V(X)=E(X^{2})-[E(X)]^{2}\\=[(1^{2}\times \frac{1}{6})+(2^{2}\times \frac{1}{6})+...+(6^{2}\times \frac{1}{6})]-(3.5)^{2}\\=2.92](/tpl/images/0555/2580/d3fd4.png)
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1 point) Suppose we roll a fair six-sided die and sum the values obtained on each roll, stopping onc...
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