The probability of buying a movie ticket with a popcorn coupon is 0.608. If you buy 10 movie tickets, what is the probability that more than 3 of the tickets have popcorn coupons? (Round your answer to 3 decimal places if necessary.)

the probability that more than 3 of the tickets have popcorn coupons is 0.951

Step-by-step explanation:

We would assume a binomial distribution for the event of buying a movie ticket with a popcorn coupon. The formula is expressed as

P(x = r) = nCr × p^r × q^(n - r)

Where

x represent the number of successes.

p represents the probability of success.

q = (1 - r) represents the probability of failure.

n represents the number of trials or sample.

From the information given,

p = 0.608

q = 1 - p = 1 - 0.608

q = 0.392

n = 10

P(x > 3) = 1 - P(x ≤ 3)

P(x ≤ 3) = P(x = 0) + P(x = 1) + P(x = 2) + P(x = 3)

Therefore,

P(x = 0) = 10C0 × 0.608^0 × 0.392^(10 - 0) = 0.000086

P(x = 1) = 10C1 × 0.608^1 × 0.392^(10 - 1) = 0.0013

P(x = 2) = 10C2 × 0.608^2 × 0.392^(10 - 2) = 0.0093

P(x = 3) = 10C3 × 0.608^3 × 0.392^(10 - 3) = 0.038

P(x ≤ 3) = 0.000086 + 0.0013 + 0.0093 + 0.038 = 0.049

Therefore,

P(x > 3) = 1 - 0.049 = 0.951

a. turk and mcalister

b. howard, mission, and market

c. yes. since streets end some do not cross yet are not parallel to others. example: mcalister and 5th

step-by-step explanation:

parallel lines are lines which do not intersect ever and look a lot like railroad tracks. turk, mcalister and golden gate are examples of these.

intersect are streets which cross each other and a car on one can reach the other. howard, mission, and market intersect with 6th.

skew lines are lines which neither intersect nor are parallel. these lines exist here because some streets end and never intersect another like mcalister and 5th.

what is the question?

step-by-step explanation: