A person places $641 in an investment account earning an annual rate of 5.8%, compounded continuously. Using the formula V = Pe^{rt}V=Pe rt , where V is the value of the account in t years, P is the principal initially invested, e is the base of a natural logarithm, and r is the rate of interest, determine the amount of money, to the nearest cent, in the account after 2 years.

r=5.8\%=0.058

r=5.8%=0.058

Move decimal over two places

P=641

P=641

Given as the pricipal

t=2

t=2

Given as the time

V=Pe^{rt}

V=Pe

rt

V=641e^{0.058( 2)}

V=641e

0.058(2)

Plug in

V=641e^{0.116}

V=641e

0.116

Multiply

V=719.8404\approx 719.84

V=719.8404≈719.84 - answer

Use calculator and round to nearest cent

Step-by-step explanation:

555.97

Step-by-step explanation:

Move decimal over two places

r = 5.2% = 0.052

Given as the principal

P = 207

Given as the time

t = 19

V=Pe^rt

Plug in

V = 207e^0.052(19)

Multiply

V = 207e^0.988

Use calculator and round to nearest cent

V = 555.9725 ≈ 555.97

50 min

step-by-step explanation:

they will be decreasing both their times in half

60 / 2 = 30

40/2 = 20

30 + 20 = 50

hey there!

if she's saving for six months, let's divide the total number we need for the trip by six, dividing it into the amount that needs to be saved for each month.

500 ÷ 6 =

she needs to save at least this amount each month, so we should use this symbol: ≥

let x be the amount she saves each month.

your final answer is x ≥

hope this !