In a sample of 50 cases of juice, 3 had defects. The sampling method had a margin of error of 0.04.
What is the interval estimate for the proportion that would have defects in the form
(lower limit, upper limit)?
0
(0.6, 0.14)
O (0.1,0.9)
0 (0.02,0.10)
0
(0.4,0.12)

the margin of error is on either side of that

(0.02, 0.10)

step-by-step explanation:

always plug in x. in this case, x equals 4.

i'm going to first solve 4(2+3x)

1) 4(2+3(4)) use pemdas to solve.

i'm going to multiply whats in the parenthesis first, so 3 times 4=12.

2)4 (2+12) i'm then going to multiply 4 by both numbers in the parenthesis (because multiplying comes before adding)

4 times 2= 8.   4 times 12= 48

4) (8+48)= 56 (answer)

i'm then going to solve 8+12x and plug in 4 for x.

1) 8 +12(4)

multiplying comes before adding, so i'm gonna multiply 12 and 4.

12 times 4= 48.

2) 8+48=56

both equal the same!