Cindy has a jar of mixed nuts. There are two pecans, three peanuts, and one cashew in the jar. Cindy grabs two nuts and gives them to her friend, Paul, and he eats them. What is the probability of Paul eating a cashew and a pecan?

A 1/18

B 1/15

C 2/11

D 1/4

B 1/15

Step-by-step explanation:

This is non-replacement choosing, so no matter which order is that (cashew-pecan or pecan-cashew) the probability is either

1 / 6 x 2 / 5  or 2 / 6 x 1 / 5  = 2/30 = 1/15

step-by-step explanation:

i think something is missing in your question because y-1=(x-12) would not pass through the point (-4,-3). because if you replace x by -4 your are supposed to find y=-3 which is not the case her. if you replace x by -4 you find =-15.

i assume the right equation is y-1=1/4*(x-12) because this one is passing through both your points (if you are interested to know how i found that out i can tell you).

in this equation if i replace x by -4 i find y=-3 and if i replace x by 12, i find y=1 so the line representing this equation is passing through those 2 points.

then the standard form of the equation is finding an expression of y in function of x

y-1=1/4*(x-12)

y=x/4-3+1

y=x/4-2

hope that .

do you confirm there was a mistake in the question?