Ryan has $25 to spend on a bouquet of flowers for Valentine's Day! He wants the bouquet to have 4 roses. Roses cost $2.95. He also wants carnations in the bouquet carnations cots $1.25 each. Ryan says he can buy 12 carnations with the money he has. Is Ryan correct?

Ryan is wrong, he cannot buy 12 Carnations on that budget

Step-by-step explanation:

In this question, we want to evaluate the validity of correctness of a claim made by Ryan who is purchasing some flowers for valentine and has a budgeted amount of money to spend.

Firstly, we identify the total amount of money he has to spend. This is $25. Now we look at his choice. He wants the bouquet to have four roses.

We proceed to calculate the cost of having four roses in his bouquet. Since one rose cost $2.95, then four roses will cost a total of $2.95 * 4 = $11.8

Now, the left over amount he has to spend on carnations would be the total minus the amount he had spent on buying 4 roses. That would be $25-$11.8 = $13.2

What is left now to completely answer this question is to see if $13.2 would be enough for the 12 carnations he had proposed he is going to buy. To check this, we simply divide the left over amount by the amount that a carnation cost. From the question, we can see that a Carnation cost $1.25, thus the number of carnations that is buy-able with $13.2 is $13.2/$1.25 = 10.56 and that is approximately equal to 11.

Thus we can see that Ryan is not correct

answer: sine

step-by-step explanation:

the length of o'p' is .

step-by-step explanation:

it is given that the quadrilateral m'n'o'p' is the image of quadrilateral mnop after dilation.

the center of dilation is origin and the scale factor is 1.5.

in dilation the image and preimge are similar figures. it means the sides of image and preimage are proportional.

the scale factor is defined as

the scale factor is 1.5.

multiply both sides by op.

note: if the value of op is given, then multiply the value of op with 1.5 to get the length of side o'p'.

therefore length of o'p' is .