Can you guys please help. I really don't know how to solve this

The inequalities that can be used to represent this problem are x < 0 or x > 5. On the number line, you will want to place an open circle on both 0 and 5. The open circle signifies that x is not equal to these values, but is greater or less than. On the open circle on 0, draw an arrow pointing left, toward the negative values. On the open circle on 5, draw an arrow pointing right, toward the positive values.

Hope this helps!! :)

i get you, what you should do is think of the positive things that would come out of it. it will make yours parents proud and raise your grade. you should always try and if you can't focus tell the teacher.

hello from mrbilldoesmath!

answer:   (7x + 6y) ( 49x^2 - 42xy + 36y^2)

discussion:

in general, the factorization of a^3 + b^3 is

a^3 + b^ 3 = (a + b) ( a^2 - ab + b^2)

in our case note that 343 = 7^3 and 216 = 6^3 so the equation becomes:

343x^3 + 216y^3 = (7x)^3 + (6y)^3

if you think of a (above) as 7x and b as 6y the factorization becomes

343x^3 + 216y^3 =

((7x + 6y) (   (7x)^2 - 7x*6y + (6y)^2)   =

(7x + 6y) ( 49x^2 - 42xy + 36y^2)

you,

mrb

(a + b) (a^2 - a b + b^2)