Steve and Michelle Neely are celebrating their 30th anniversary by having a reception at a local reception hall. They have budgeted $4,000 for their reception. If the reception hall charges $50 cleanup charge fee plus $33 per person, find the greatest number of people that they may invite and still stay within their budget

Greatest Number of People that may be invited = 48

Step-by-step explanation:

Step 1:

Let the budget be $ 4000 =Amount

Total cost per person =( $50 + $33 ) = $83

Step 2:

Greatest number of persons Steve and Michelle Neely may invite is given by

Greatest number of  Persons may be invited

                                                  = (Budget decided) / (Cost per person)

People Count = ( 4000) / ( 83) = 48.19

                        =  (48*83) + 16 = 4000

Tentatively Greatest number of people may be invited is equal to 48 and remaining budget with them is $16

b

2

−

b

b

3

+

7

b

2

+

14

b

+

6

%

−

3

b

3

+

7

b

2

+

14

b

+

6

%

step-by-step explanation:

3 1/3 x 2 3/5 = 8 2/3

step-by-step explanation:

just multiply the first number by the second number to get your answer.