Jenna solved the equation 2x^2 +5x - 42 = 0 . She stated that the solutions to the equation were 7/2 and -6. Do you agree with Jenna's solution? Explain why or why not.

Yes. Her solution is correct.

Step-by-step explanation:

Let's check if Jenna solution is correct:

To solve the equation 2x^2 +5x - 42 = 0, we can use Bhaskara's formula:

D = b^2 - 4ac = 25 + 4*2*42 = 25+336 = 361

sqrt(D) = 19

x1 = (-5 + 19)/4 = 14/4 = 7/2

x2 = (-5 - 19)/4 = -24/4 = -6

We must agree with Jenna's solution, because the values she found as solution are correct: with we replace these values of x in the equation, we will find 0 = 0, which is correct and proves that these values are the solution of the equation.

x = central angle apc = measure of minor arc ac

the two angles x and 30 add to 180, so x+30 = 180 and x = 180-30 = 150. the measure of minor arc ac is 150 degrees.

what we need to do from here is find the circumference and then multiply it by x/360 since there are 360 degrees in a circle. in this case, x = 150, so x/360 = 150/360 = 15/36 = 5/12. the shortest distance along the curve from a to c is 5/12 of the distance around the entire circle (aka circumference)

c = circumference

c = pi*d

c = pi*24

c = 24pi

now multiply this by 5/12 to get

distance along minor arc ac = (5/12)*(circumference)

distance along minor arc ac = (5/12)*(24pi)

distance along minor arc ac = 10pi

the formula you can use is

l = (x/360)*pi*d

with

l = length of minor arc

x = central angle

d = diameter

which essentially is the steps we took though a bit differently.