Find the equation for the line passing through the point (-1, 1) and perpendicular to the line whose equation is -2x-3y-5=0

The answer to your question is    y = 3/2x + 5/2      

Step-by-step explanation:

Data

P (-1, 1)

⊥ -2x - 3y - 5 = 0

Process

1.- Find the slope of the original line

           -2x - 3y - 5 = 0

                  -3y = 2x + 5

                     y = -2/3x - 5/3

Slope = -2/3

2.- Find the slope of the new line

Slope = 3/2

3.- Find the equation of the line

          y - y1 = m(x - x1)

-Substitution

          y - 1 = 3/2(x + 1)

-Simplification

          y - 1 = 3/2x + 3/2

             y  = 3/2x + 3/2 + 1

-Result

              y = 3/2x + 5/2                    

second option

step-by-step explanation:

the measures of a triangle equal 180. use that to find x.

2x+3x+4x=180

9x=180

9x/9=180/9

x=20

now you know x, you know angle a is 40°, angle b is 60°, angle c is 80°.

because angle a is 40°, the first option doesn't work.

because angle b is 60°, the second option does work.

when you add angle a and b, you get 100°. complementary means it equals 90°, so the third option doesn't work.

when you add angle a and c, you get 120°, which is not 100.

could u provide us some answer choices or hmm idk maybe a table for us to anser with ? ?