Thanksgiving spending, Part II. Exercise 4.14 provides a 95% confidence interval for the average spending by American adults during the six-day period after Thanksgiving 2009: ($80.31, $89.11). (a) A local news anchor claims that the average spending during this period in 2009 was $100. What do you think of her claim? (b) Would the news anchor’s claim be considered reasonable based on a 90% confidence interval? Why or why not? (Do not actually calculate the interval.)

(a) The claim made by the local news anchor is not correct that the average spending during this period in 2009 was $100.

(b) The news anchor’s claim will not be considered reasonable based on a 90% confidence interval.

Step-by-step explanation:

The (1 - α)% confidence interval for the population mean is,

The factors affecting the width of the interval are:

In this case the 95% confidence interval for the average spending by American adults during the six-day period after Thanksgiving 2009 is provided as ($80.31, $89.11).

On making decisions about a hypothesis test based on confidence interval, the rule followed is:

If the confidence interval contains the null value then the null hypothesis will be accepted or else rejected.

(a)

The hypothesis to test the claim made by the local newspaper anchor is:

H₀: μ = $100 vs. Hₐ: μ ≠ $100

The 95% confidence interval does not contains the null value, i.e. $100.

Thus, the null hypothesis will be rejected at 5% level of significance.

Conclusion:

The claim made by the local news anchor is not correct that the average spending during this period in 2009 was $100.

(b)

The critical value of the z-statistic increases on increasing the confidence level and decreases on decreasing the confidence level.

So if the confidence level was 90% instead of 95% the critical value of z will be decreased.

And since the critical value is directly proportional to the width of the interval, the width will also decrease on decreasing the critical value.

So the 90% confidence interval will be much narrower than the interval, ($80.31, $89.11).

Hence the null value will still not be included in the interval.

Thus, the news anchor’s claim will not be considered reasonable based on a 90% confidence interval.

choice b is correct

step-by-step explanation:

we have been given the following system of inequalities;

we are required to graph the solution to the system of inequalities. using a graphing tool, the graph of the system is as shown in the attachment. the continuous line represents the graph of while the dotted line represents .

care to share were the trapezoid shown is ?