Bennett purchase some beef and some chicken for a family barbecue the beef cost was $6.30 per pound and the chicken cost $4.60 per pound he bought a total of 12 pounds of me and spent $63.70 how much of each type of meat did he purchase

He bought 7 pounds of chicken and 5 pounds of beef

Step-by-step explanation: We shall start by assigning letters to the unknown variables. Hence, let b represent a pound of beef and let c represent a pound of chicken. If Bennett bought a total of 12 pounds of meat, then we can express this as

b + c = 12

Then if he spent a total of $63.7 on both types of meat, we can write it out as

6.3b + 4.6c = 63.7

We now have a pair of simultaneous equations, which are

b + c = 12 (1)

6.3b + 4.6c = 63.7 (2)

In equation (1) we shall make b the subject of the equation

b = 12 - c

We now substitute for the value of b into equation (2)

6.3(12 - c) + 4.6c = 63.7

75.6 - 6.3c + 4.6c = 63.7

We collect like terms and we now have

-1.7c = -11.9

Divide both sides of the equation by -1.7

c = 7.

Having found the value of c, we can now substitute for the value of c into equation (1)

b + c = 12

b + 7 = 12

Subtract 7 from both sides of the equation

b = 5.

Therefore, Bennett purchased 7 pounds of chicken and 5 pounds of beef.

false

step-by-step explanation:

4y - 6 + 4y^2 - 9

before simplifying this contains 4 terms

after simplifying

4y -15 + 4y^2

it contains 3 terms