Mathematics, 19.03.2020 03:13 lizzy6629

The front face of Ivan's MP3 player is a rectangle that is 2 1/2 inches long the width is 7/8 of the length what is the area of the front face of the MP3 player

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Answer from: Annsanchez5526

Therefore,

Are of the front face of Ivan's MP3 player is 2.1875 inches².

Step-by-step explanation:

Given:

The front face of Ivan's MP3 player is a rectangle

Let the length of a front face of Ivan's MP3 player be

$Length=2\dfrac{1}{2}=2.5\ inches$

and Width of front face of Ivan's MP3 player be

$Width=\dfrac{7}{8}=0.875\ inches$

To Find:

Area of front face of Ivan's MP3 player =?

Solution:

We have area of rectangle given as

$\textrm{Area of Rectangle}=Length\times Width$

Substituting the given values we get

$\textrm{Area of front face of Ivan's MP3 player}=2.5\times 0.875=2.1875\ inches^{2}$

Therefore,

Are of the front face of Ivan's MP3 player is 2.1875 inches².

Answer from: Quest

c. 27 units.

step-by-step explanation:

we are told that in circle a, ∠bae ≅ ∠dae.

we can see from our given diagram that in $\delta bea$ and $\delta dea$ ;

$ba=da$ , as these are radii of our given circle.

$ea=ea$

therefore, $\delta bea\cong \delta dea$ by sas congruence postulate.

hence, side be will be equal to side de as corresponding parts of congruent triangles are congruent. so we can set an equation to find the value of x as:

$3x-24=x+10$

$3x-x=24+10$

$2x=34$

$x=\frac{34}{2}$

$x=17$

now let us substitute x=17 in the expression for the length of be.

$\text{length of be}=3x-24$

$\text{length of be}=3\cdot 17-24$

$\text{length of be}=51-24$

$\text{length of be}=27$

therefore, length of be will be 27 units and option c is the correct choice.

In circle a, ∠bae ≅ ∠dae. what is the length of be? 14 units 17 units 27 units 34 units

Answer from: Quest

la parábola es el lugar

geométrico en el cual los puntos tienen una distancia idéntica, equidistantes,

de un punto denominado foco, f, y una recta denominada directriz

el radio vector de una

parábola es el segmento que existe entre un punto cualquiera y el foco.

por la ecuación se observa

que la parábola abre hacia la derecha, por lo cual podemos usar las siguientes fórmulas

la ecuación ordinaria de la

parábola es y^2 = 4px, donde p es la longitud desde el vértice de la parábola al

foco.

la fórmula de la directriz

es x + p = 0

resolviendo:

y^2-9x = 0

y^2 = 9x

4p = 9, entonces p = 9/4

entonces el foco tendrá la

coordenada f(9/4,0)

la directriz vendrá

expresada por

x + p = 0

x = -p

x = -9/4

el problema indica que la

ordenada es igual a 6, entonces

(6)^2=9x

x = 36/9

x = 4

entonces el punto al cual

hay que obtener la distancia será p(4,6)

calculando se tendrá: pf =

pf = 6,25 u

ver más en -

step-by-step explanation:

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The front face of Ivan's MP3 player is a rectangle that is 2 1/2 inches long the width is 7/8 of the...