The vertex of this parabola is at (2, -1). When the y-value is 0,

the x-value is 5. What is the coefficient of the squared term in

the parabola's equation?

2.-12

O A. 4

O B. -4

O c. -3

The coefficient is 3.

Step-by-step explanation:

The parabola has the vertex at (2,-1).

So, the equation of the parabola in vertex form will be (if its axis of symmetry is parallel to the positive x-axis)

(y + 1)² = 4a(x - 2) ........... (1)

Now, the point (5,0) will satisfy the above equation.

Hence, 1 = 4a(5 - 2) = 12a

⇒

So, from equation (1) we get,

⇒ 3(y + 1)² = (x - 2)

⇒ 3y² + 6y + 3 = x - 2

⇒ 3y² + 6y + 5 = x

Therefore, the coefficient of the squared term i.e. y² in the above parabola equation is 3. (Answer)

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