Consider randomly selecting a single individual and having that person test drive 3 different vehicles. define events a1, a2, and a3 by a1 = likes vehicle #1 a2 = likes vehicle #2 a3 = likes vehicle #3. suppose that p(a1) = 0.55, p(a2) = 0.75, p(a3) = 0.70, p(a1 ∪ a2) = 0.90, p(a2 ∩ a3) = 0.30, and p(a1 ∪ a2 ∪ a3) = 0.84. -g

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step-by-step explanation:

37/3

step-by-step explanation:

step 1: simplify both sides of the equation.

7x+8(x+

1

4

)=3(6x−9)−8

7x+(8)(x)+(8)(

1

4

)=(3)(6x)+(3)(−9)+−8(distribute)

7x+8x+2=18x+−27+−8

(7x+8x)+(2)=(18x)+(−27+−8)(combine like terms)

15x+2=18x+−35

15x+2=18x−35

tep 2: subtract 18x from both sides.

15x+2−18x=18x−35−18x

−3x+2=−35

step 3: subtract 2 from both sides.

−3x+2−2=−35−2

−3x=−37

step 4: divide both sides by -3.

−3x

−3

=

−37

−3

x=

37

3

answer: 1 + 1 = 11

step-by-step explanation: