Sharon is jumping from an 18-foot diving board with an initial upward velocity of 4 ft/s. when sharon jumps, megan throws a beach ball up to sharon with an initial upward velocity of 16 ft/s from a height 5 feet off the ground. to the nearest hundredth of a second, how long after she jumps does the ball reach sharon? 0.65 seconds 0.92 seconds 1.08 seconds 1.15 seconds

1.15 seconds.

Step-by-step explanation:

We are given that Sharon is jumping from an 18-foot diving board with an initial upward velocity of 4 ft/s. when Sharon jumps

So, equation of Sharon :

Megan throws a beach ball up to Sharon with an initial upward velocity of 16 ft/s from a height 5 feet off the ground. to the nearest hundredth of a second

So, equation of Megan :

Now we are required to find  how long after she jumps does the ball reach Sharon.

Thus after what time the height will be same

So,  

Thus the ball reach the Sharon after 1.15 seconds.

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step-by-step explanation: