What is the equation of a line that is parallel to -32 + 4y = 4 and passes through the point
(4, 0)?

-8x + y = -32

Step-by-step explanation:

Where's the variable x?  I will assume you meant -32x + 4y = 4.

Any line parallel to this given line has an equation of the same form but a different constant:

Substituting the coordinates (4, 0) into -32(4) + 4(0) = C, we get:

-128 + 0 + C, and so C = -128, and:

the desired equation is -32x + 4y = -128

or, after reduction, -16x + 2y = -64, or -8x + y = -32

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step-by-step explanation:

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answer: (-8,4) are the coordinates of a

step-by-step explanation:

let the side of square abcd is x .

thus the area of square abcd is .

now, by the diagram area of triangle ead= 1/2 × ea × ad = 1/2 × ea × x

( because ad is the side of square)

and, according to the question,

the areas of square abcd and right ead are equal.

⇒

⇒ea=2x

thus, ea: ab=2: 1

therefore, point a divides line segment eb into the ratio 2: 1.

⇒ by sectional formula coordinates of a are,

=

=

=(-8, 4)

thus the coordinates of a are (-8,4)