Graph a line that contains the point (-5,6) and has a slope of 2/3

y= 2/3x + 28/3

Step-by-step explanation:

First, write your equation as y=2/3x+b. Plug in your coordinate into the equation, it should look like this: 6=2/3(-5)+b. Multiply 2/3 by -5 to get -10/3. It should look like this: 6= -10/3+b. Add 10/3 to both sides to get your y-intercept of 28/3. Go back to your original equation and plug 28/3 into b. This is your final equation: y= 2/3x + 28/3. Hope this helped!

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step-by-step explanation: