What is the distance between (–2 and one-half, –3) and (1, –3)?

The distance between the points is 2 and 1/2 units.

Step-by-step explanation:

We want to calculate the distance between the points:

First, to calculate the difference between the vectors (a,b) and (c,d) we have:

(a, b) - (c, d) = (a -c, b - d)

(-2 + 1/2, -3) and (1, - 3)

First, we calculate the difference of the two ponts:

(-2 + 1/2, -3) - (1, - 3) = (-2 + 1/2 - 1. -3 - (-3)) = (-3 + 1/2, 0 )

now this is the distance vector, we can calculate the magnitude of the distance by calculating the magnitude of this vector, this is:

d = √((-3 +1/2)^2 + 0^2) = √(-3 + 1/2)^2 = (3 - 1/2) = 2 + 1/2

y=3n + 1

step-by-step explanation:

this is wrong because it says the second number is one less and i added one instead