A gardener is planting two types of trees:

Type A is 3 feet tall and grows at a rate of 15 inches per year.

Type B is 6 feet tall and grows at a rate of 11 inches per year.

Algebraically determine exactly how many years it will take for these trees to be the same height.
i dont get it ive tried everything that i know and still got stuck

Solution:

Let "x" be the number of years

Type A is 3 feet tall and grows at a rate of 15 inches per year

1 feet = 12 inches

3 feet = 12 x 3 = 36 inches

Equation: 36 + 15x eqn 1

Type B is 6 feet tall and grows at a rate of 11 inches per year

6 feet = 6 x 12 = 72 inches

Equation: 72 + 11x eqn 2

For both trees to be of same height, eqn 1 must be equal to eqn 2

36 + 15x = 72 + 11x

15x - 11x = 72 - 36

4x = 36

Thus it takes 9 years for both trees to be of same height

answer: x=3 and y=4

step-by-step explanation:

answer: i wpould go with c

step-by-step explanation: