4- x2 =-32
The equation above is true for what value of x, where
x>0?

x= -6

Step-by-step explanation:

first you want to get rid of the 4 so on both sides you subtract 4

4-x²=-32

-4      -4  that will then make the problem

-x²= -36 to get rid of the square you must do the opposite, square root () so it will get rid of the ²

-x= 6 then you have to get rid of the neggative on x so you will add a negative to 6

x=-6

jml angle lkj & angle mj = lm

it would be a on edgenuit y

the diagram below is your final answer