Tom's house is located at point (-2, 3) and the school is located at point (-2, -5). What is the distance between Tom's house and the school? Group of answer choices

8 units.

Step-by-step explanation:

We have been given that Tom's house is located at point (-2, 3) and the school is located at point (-2, -5). We are asked to find the distance between Tom's house and the school.

We will use distance formula to solve our given problem.

Let point and point .

Upon substituting the coordinates of given points in distance formula, we will get:

Therefore, the distance between Tom's house and the school is 8 units.

the smallest possible measurement of the width is 14 feet

step-by-step explanation:

let's assume length of parallelogram is 'l'

width of parallelogram is 'w'

the perimeter of a parallelogram must be no less than 40 feet

so, we get

we are given

length of parallelogram is 6 feet

so,

l=6

we can plug it

now, we can solve for w

subtract both sides by 12

divide both sides by 2

and we get

so,

the smallest possible measurement of the width is 14 feet