A bag contains 15 green, 18 yellow, and 16 orange balls. One ball is randomly selected.
To the nearest percent, what is the probability of the event?
Drag and drop the correct value into the box.
P(yellow) =
31%
33%
37%
42%

37%

Step-by-step explanation:

n( green ) = 15

n( yellow) = 18

n(Orange) = 16

Total = 49

P(yellow) = n(yellow) / Total number

P(yellow) = 18/49

P(yellow) = 0.367

converting to percentage

P(yellow) = 0.367 x 100 = 36.7

To the nearest percent

P(yellow) = 37%

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i got 86 for this

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