A person invests 5000 dollars in a bank. The bank pays 6.5% interest compounded monthly. To the nearest tenth of a year, how long must the person leave the money in the bank until it reaches 11300 dollars?

13.6 years

Step-by-step explanation:

We would apply the formula for determining compound interest which is expressed as

A = P(1+r/n)^nt

Where

A = total amount in the account at the end of t years

r represents the interest rate.

n represents the periodic interval at which it was compounded.

P represents the principal or initial amount deposited

From the information given,

P = $5000

A = $11300

r = 6% = 6/100 = 0.06

n = 12 because it was compounded 12 times in a year.

Therefore,.

11300 = 5000(1 + 0.06/12)^12 × t

11300/5000 = (1 + 0.005)^12t

2.26 = (1.005)^12t

Taking log of both sides, it becomes

Log 2.26 = 12tlog 1.005

0.354 = 12t × 0.0022

0.354 = 0.0264t

t = 0.354/0.026

t = 13.6 years

c

step-by-step explanation:

26 is 33.33% of 78

step-by-step explanation:

26 is what percent of 78?

26 is p% of 78

equation: y = p% * x

solving our equation for p

p% = y/x

p% = 26/78

p = 0.3333

convert decimal to percent:

p% = 0.3333 * 100 = 33.33%