Solve for x in the equation x squared minus 10 x + 25 = 35.
x = 5 plus-or-minus 2 StartRoot 5 EndRoot
x = 5 plus-or-minus StartRoot 35 EndRoot
x = 10 plus-or-minus 2 StartRoot 5 EndRoot
x = 10 plus-or-minus StartRoot 35 EndRoot

x = 5 ±

Step-by-step explanation:

Given

x² - 10x + 25 = 35 ( subtract 25 from both sides )

x² - 10x = 10

Using the method of completing the square

add ( half the coefficient of the x- term )² to both sides

x² + 2(- 5)x + 25 = 10 + 25

(x - 5)² = 35 ( take the square root of both sides )

x - 5 = ± ( add 5 to both sides )

x = 5 ±

That is the second option on list

d, x=8

step-by-step explanation:

simplifying

4x + -5 = 2x + 11

reorder the terms:

-5 + 4x = 2x + 11

reorder the terms:

-5 + 4x = 11 + 2x

solving

-5 + 4x = 11 + 2x

solving for variable 'x'.

move all terms containing x to the left, all other terms to the right.

add '-2x' to each side of the equation.

-5 + 4x + -2x = 11 + 2x + -2x

combine like terms: 4x + -2x = 2x

-5 + 2x = 11 + 2x + -2x

combine like terms: 2x + -2x = 0

-5 + 2x = 11 + 0

-5 + 2x = 11

add '5' to each side of the equation.

-5 + 5 + 2x = 11 + 5

combine like terms: -5 + 5 = 0

0 + 2x = 11 + 5

2x = 11 + 5

combine like terms: 11 + 5 = 16

2x = 16

divide each side by '2'.