The formula for finding the present value of an item that depreciates yearly is v=c-crt. In this formula, v is the present value, c is the original cost, r is the rate of depreciation per year, and t is the number of years that have passed. After 4 years, what is the value of a car originally costing $30,000 that depreciated at a rate of 0.1 per year?
The value of the car after 4 years is $?

The value of the car after 4 years is $18,000

Step-by-step explanation:

Formulas

The model used to compute the present value of an item that depreciates yearly is

Where v is the present value, c is the original cost, r is the rate of depreciation per year, and t is the number of years that have passed.

We are required to find the value of a car originally costing c=$30,000 that depreciated at a rate of r=0.1 per year after t= 4 years

We plug in the given data

The value of the car after 4 years is $18,000

solution:

the given function is ,

      =

the three roots of this quadratic function is , 0 ,8 and 10.all the roots are real and rational.

if a quadratic equation is of the form ,

sum of the roots = a + b +c= 0+8+10=18=  

product of roots taken two at a time = a b + b c+ c a = 0+80+0=80 =  

product of roots = a b c = 0=  

there are 11 doors in a hall starting from 0 to 11.the entry in the hall is permitted through gate number 0 and exit is allowed through only gate number 8 and 10.so, three roots(0,8,10) of quadratic function is given by entry and exit route of this hall.

x coordinate can be written by using the formula, x= x1 + 2/5(x2 - x1)

step-by-step explanation:

formula

x = x1 + p/w(x2 - x1)

let the line segment ab with a(x1,y1) and b(x2,y2)

a point(x,y) divide ab in the ratio, 2: 3 the x coordinate can be written as

x = x1 + p/w(x2 - x1)

here p=2 and w = 2+3

therefore,

x coordinate can be written by using the formula, x= x1 + 2/5(x2 - x1)

similarly y coordinate y = y1 + 2/5(y2 - y1)