Miguel stated that any monomial can be a cube root Sylvia disagreed and said that a monomial cube root must have
exponents divisible by 3 Who is correct, and why?
Sylvia is correct Any variable term, when it is cubed, always has an exponent divisible by 3
Miguel is correct Any monomial can be a perfect cube root because, when it is cubed, the variables will have exponents
divisible by 3
Sylvia is correct in order for the cube to have exponents that are divisible by 3, the cube root has to be divisible by 3.
Miguel is correct Sylvia confused the perfect square root with the perfect cube root