State if the point (-3, -2) is a solution to the system of equations below.
x^2 + y^2 + x - 10y - 3=0
x+y= -4

A) Since (-3,-2) does satisfy both equations, it is a solution to the system.

B) Since (-3,-2) does not satisfy both equations, it is not a solution to the
system.

C) Since (-3,-2) does satisfy both equations, it is not a solution to the system.

D) Since (-3,-2) does not satisfy both equations, it is a solution to the system.

B) Since (-3,-2) does not satisfy both equations, it is not a solution to the

system.

Step-by-step explanation:

The given system of equations is:

If (-3,-2) is a solution, then it must satisfy both equations:

Let us substitute into the first equation to get:

Evaluate the exponents;

This is not true

Also when we substitute into the scond equation, we get;

This is also false.

Therefore the point is not a solution.

idk

step-by-step explanation:

step-by-step explanation:

this can be solved first with pythagorean theorem, which tells us to square both legs of the triangle and sum it. this will be equal to the square of the hypotenuse.

the hypotenuse is the side "opposite" the 90 degree angle, which is x.

so we can write using pythagorean theorem,

simplifying:

to further simplify this radical, we need to use the property  

thus