Which point is on the circle whose equation is x^2 + y^2 = 289
1) (-12,12) 2) (7,-10) 3) (-1,-16) 4) (8,-15)

Point 4) (8, -15) is on the circle.

Step-by-step explanation:

Step 1:

To determine which point lies on the circle equation, we substitute the different x and y values in the equation and check to see which best satisfies the values in the equation.

The equation of the circle is

Step 2:

When 288 ≠ 289.

When 149 ≠ 289.

When 257 ≠ 289.

When

So the fourth set of values is on the circle.

b

step-by-step explanation: