Which series of transformations would transform triangle A into similar triangle A' in Quadrant IV? A. Rotate triangle A 90 clockwise about the origin then translate five units up B. Dilate triangle A by a scale factor of 4. Translate triangle A to the left. C. Reflect triangle A across the y-axis and then translate the triangle 3 units up and 2 units to the right. D. Reflect triangle A across the x-axis and then reflect the triangle across the y-axis.

option D

Step-by-step explanation:

It is required to transform triangle A into similar triangle A' in Quadrant IV.

The given triangle in Quadrant II.

We will check the options:

A. Rotate triangle A 90 clockwise about the origin then translate five units up.

Wrong because  triangle A' will be at Quadrant I.

B. Dilate triangle A by a scale factor of 4. Translate triangle A to the left.

Wrong because  triangle A' will be at Quadrant II.

C. Reflect triangle A across the y-axis and then translate the triangle 3 units up and 2 units to the right.

Wrong because  triangle A' will be at Quadrant I.

D. Reflect triangle A across the x-axis and then reflect the triangle across the y-axis.

True Because reflection triangle A across the x-axis, the first image will be at  Quadrant III, then reflection the first image across the y-axis, we will get triangle A' will be at Quadrant IV.

So, the answer is option D

f(x) = x^3 -2x^2 -3x

x( x^2 -2x-3)

x( x^2 +x -3x -3)

x( x(x+1) -3(x+1))

x( x-3)( x+1)

so zeroes are 0, 3,-1

its (2) option