6 Write an equation in point-slope form given the points (-1,-7) and (2, 5). a. y - 5 = 4 (x - 2) b. y + 5 = 4 (x + 2) c. y - 2 = 4 (x - 5) d. y + 2 = 4 (x + 5)

A - y - 5= 4(x - 2)

Step-by-step explanation:

First find slope with the two points given

( -1 , -7) and ( 2 , 5)

Using

m = y_2 - y_1 / x_2 - x_1

m - slope

x_1 = -1

y_1 = -7

x_2 = 2

ÿ_2 = 5

Inserting the values

m = 5 - (-7) / 2 - (-1)

= 5 + 7 / 2 + 1

= 12 / 3

= 4

Slope is 4

Then let's proceed

y - y_1 = m ( x - x_1)

using ( 2 , 5) as x_1 and y_1 respectively

x_1 = 2

y_1 = 5

m = 4

y - 5 = m ( x - 2)

m = 4

y - 5 = 4 ( x - 2)

We are asked to give the answer in point slope form

the correct functions are

h(x) = 3x + 2  

g(x) = 2^x

step-by-step explanation:

i proceed to calculate the different values ​​of k (x)

case 1)  k(x) = g(x) ∘ h(x)

g(x) ∘ h(x)=g(h(x))

k(x) = [2]^[3x + > is the option  4. k(x) = 2^(3x + 2 )

case 2)  k(x) = g(x) + h(x)

k(x) = [2^x]+[3x + 2]=2^x+3x+> is the option  1.) k(x) = 2^x + 3x + 2

case 3)k(x) = h(x) ÷ g(x)

k(x) =  [3x + 2]/[2^x]=3x/(2^x)+2/(2^x)=3x*(2^-x)+2^(1-x)

is the option  3.)   k(x) = (3x)2^(-x) + 2^(-x + 1 )

case 4)k(x) = g(x) - h(x)

k(x) =  [2^x]-[3x + 2]=2^x-3x-> is the option  2.) k(x) = 2^x - 3x - 2 

case 5)  k(x) = g(x) × h(x)

k(x) = [2^x]*[3x + > is the option  5.) k(x) = 2^x(3x + 2)

case 6)k(x) = h(x) ∘ g(x)

h(x) ∘ g(x)=h(g(x))

k(x)=3*[2^x]+> is the option  6. k(x) = 3(2^x) +2