The surface area of a cube is increasing at a rate of 151515 square meters per hour. At a certain instant, the surface area is 242424 square meters. What is the rate of change of the volume of the cube at that instant (in cubic meters per hour)

Therefore the volume of cube is increasing at a rate cubic meter per hour.

Step-by-step explanation:

Given that the surface area of a cube is increasing at a rate 15 square meter per hour.

i.e   square meter per hour.

A = the surface area of the cube

At a certain instant the surface area is 24 square meter.

At that time the side of the cube be x.(let)

The surface area of the cube is =6 x²

According to problem,

6 x² = 24

⇒x= 2

At that time the side of the cube was 2 meter.

Again,

A= 6x²

Differentiating with respect to t

Putting

The volume of the cube is v = x³

v = x³

Differentiating with respect to t

Putting

Therefore the volume of cube is increasing at a rate cubic meter per hour.

omg what happend to your question? if you could edit this question i can

step-by-step explanation:

-4

step-by-step explanation:

do 6-10=

if u need it to be negative.