A fire engine starts pumping water at 9:20 am at the rate of 800 gallons per minute. Another fire engine, pumping at the rate of 1000 gallons per minute, starts at 9:30 am. At what time will the two engines have pumped the same number of gallon

At 10:10 am

Step-by-step explanation:

Hi to answer this question we have to write a system of equations:

Where m: pumping time of the engine

Because it starts 10 minute later  

So, putting together both equations:

800m = 1000(m-10)

800m = 1000m - 10000

10000 = 1000m-800m

10000= 200m

10000/200=m

50 =m (50 minutes after the first engine starts)

So, 9:20 am + 50 minutes : 10:10 am .

the answer is 510

step-by-step explanation:

15 • 13 = 195

15 • 12 = 180

15 • 5 = 75

12 • 5 = 60

195 + 180 = 375

375 + 75 = 450

450 + 60 = 510